Wednesday, February 16, 2005
Endgame Stuff Part 2
I found a great game viewing applet at the ICC. If you found my last post too easy, try this: Endgame link
Finished circle 6 of 81-120.
Comments:
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In a comment in your previous post you said about the endgame position you give in this post: "There is a solution, with a number of variations: 1.Ke3 f2 2.Qb5 f1=Q 3.Qxf1+ Kb2 4.Qb5+ {take your pick here}...Ka1 5.Qe2 Kb1 6.Kd3.
But what if black plays on move 4. Kc1 instead of Ka1??
logis
But what if black plays on move 4. Kc1 instead of Ka1??
logis
# posted by 
: 6:24 PM
: 6:24 PM
Well if you started like me, you get the less correct
1. Ke3 f2 2. Qb5 f1=Q 3. Qxf1+ Kb2 4. Qb5+ Kc1 5. Qf1+ Kb2 6. Qe2+ Kb1 7.Kd3 and then you need a Knight promotion for Black not to be mated on 8. This is looks sufficient to win in variations like 6...Ka3 7.Qd3+ Kb2 8.Qd2+ Kb3 (Kb1? Kd3!) 9.Qc1 and
6....Kb3 7.Qd1+ Kb2 8.Qd2+ Kb3 (Kb1? Kd3!) 9.Qc1 and the a1 square is covered.
BUT
5.Qc4+! followed by 6.Kd3 or Kd2 mates no matter how Black promotes ;).
1. Ke3 f2 2. Qb5 f1=Q 3. Qxf1+ Kb2 4. Qb5+ Kc1 5. Qf1+ Kb2 6. Qe2+ Kb1 7.Kd3 and then you need a Knight promotion for Black not to be mated on 8. This is looks sufficient to win in variations like 6...Ka3 7.Qd3+ Kb2 8.Qd2+ Kb3 (Kb1? Kd3!) 9.Qc1 and
6....Kb3 7.Qd1+ Kb2 8.Qd2+ Kb3 (Kb1? Kd3!) 9.Qc1 and the a1 square is covered.
BUT
5.Qc4+! followed by 6.Kd3 or Kd2 mates no matter how Black promotes ;).
I'll add 4... Kc3 5.Qa4 leads either to a prosaic mate or lines like the ones above, and 4... Ka3 5.Qa5+ Kb2 6.Kd2 a1=Q 7.Qb4+ Ka2 8.Kc2 is nasty as well :).
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